1. Slider Range

WebDriver driver = new ChromeDriver(); driver.get("https://testautomationpractice.blogspot.com");

driver.manage().window().maximize();

WebElement left_pointer = driver.findElement(By.xpath("//div[@id='slider-range']/span[1]")); WebElement right_pointer = driver.findElement(By.xpath("//div[@id='slider-range']/span[2]")); System.out.println("Original Location of Left Pointer: " + left_pointer.getLocation()); System.out.println("Original Location of Right Pointer: " + right_pointer.getLocation());

Actions act = new Actions(driver); act.dragAndDropBy(left_pointer, 10, 0).build().perform(); act.dragAndDropBy(right_pointer, -10, 0).build().perform();

System.out.println("New Location of Left Pointer: " + left_pointer.getLocation()); System.out.println("New Location of Right Pointer: " + right_pointer.getLocation());

2. Keyboard keys : Pressing two keys simultaneously

Actions act = new Actions(driver);

act.keyDown(Keys.CONTROL) --> Pressed Control Key

act.sendKeys("A") --> Pressed Key A / sent text A

WebDriver driver = new ChromeDriver();

driver.manage().window().maximize(); WebDriverWait wait = new WebDriverWait(driver, Duration.ofMinutes(10)); // Explicit wait

driver.get("https://text-compare.com"); // TODO : The above website is the most useless website and it takes a hell lot of time to load in selenium chrome instance. Sometimes it has thrown Timeout exception as well.

var field1 = wait.until(ExpectedConditions.presenceOfElementLocated(By.xpath("//textarea[@id='inputText1']"))); field1.sendKeys("Hello");

Actions act = new Actions(driver);

// press Ctrl + A act.keyDown(Keys.CONTROL).sendKeys("A").keyUp(Keys.CONTROL).perform(); System.out.println("Control A Pressed");

// press Ctrl + C act.keyDown(Keys.CONTROL).sendKeys("C").keyUp(Keys.CONTROL).perform(); System.out.println("Control C Pressed");

// press tab act.keyDown(Keys.TAB).keyDown(Keys.CONTROL).perform(); System.out.println("TAB Pressed");

// press Ctrl + v act.keyDown(Keys.CONTROL).sendKeys("V").keyDown(Keys.CONTROL).perform(); System.out.println("Control V Pressed");

3. Keyboard keys : Pressing three keys simultaneously

Actions act = new Actions(driver); act.keyDown(Keys.CONTROL) .keyDown(Keys.SHIFT) .sendKeys("C") .keyUp(Keys.SHIFT) // Release SHIFT .keyUp(Keys.CONTROL) // Release CTRL .perform();

4. Pressing Ctrl + Click simultaneously

Actions act = new Actions(driver); WebElement submitBtn = driver.findElement(By.xpath("//button[@id='submit']")); act.keyDown(Keys.CONTROL) .click(submitBtn) // Now specifying the element to click .keyUp(Keys.CONTROL) .perform();

Should I release both keys (`CTRL` and `SHIFT`) explicitly ?

Why Both `keyUp(Keys.SHIFT)` and `keyUp(Keys.CONTROL)` Are Needed:

Selenium does not automatically release keys
- When you press multiple keys using keyDown(), Selenium keeps them held down until explicitly released with keyUp().
- If you only release one key, the other remains pressed, which may cause unexpected behavior in further actions.
Mimicking real user behavior
- If a real user presses CTRL + SHIFT + C, they naturally lift both keys after performing the action.
- Keeping SHIFT or CTRL pressed unintentionally could interfere with subsequent inputs.

Example of What Happens If You Don't Release Both:

If you release only SHIFT but not CTRL, the browser (or the webpage) might still think CTRL is pressed, affecting further actions like typing or clicking.

Final Recommendation:

✅ Always pair keyDown(KEY) with keyUp(KEY) for all modifier keys to avoid issues.

Correct Code: